\(|x+1|+|x+2|+...+|x+10|=64x\) (1)
Vì:
\(|x+1|\ge0\)
\(|x+2|\ge0\)
...
\(|x+10|\ge0\)
\(\Rightarrow |x+1|+|x+2|+...+|x+10|=64x \ge 0\)
\((1)\Leftrightarrow x+1+x+2+...+x+10=64x \)
\(\Leftrightarrow 10x+55=64x\)
\(\Leftrightarrow 54x=55\)
\(\Leftrightarrow x=\frac{55}{54}\)
Chúc bạn học tốt!