bài tập toán

Question

Làm tính chia:  

a) (6x3−7x2−x+2):(2x+1)(6x3−7x2−x+2):(2x+1)            

b) (x4−x3+x2+3x):(x2−2x+3)(x4−x3+x2+3x):(x2−2x+3) ;

c) (x2−y2+6x+9):(x+y+3)(x2−y2+6x+9):(x+y+3) .

Answer 1

 

c) (x2−y2+6x+9):(x+y+3)(x2−y2+6x+9):(x+y+3)

=(x2+6x+9−y2)(x+y+3)(x2+6x+9−y2)(x+y+3)

=[(x2+2x.3+32)−y2]:(x+y+3)[(x2+2x.3+32)−y2]:(x+y+3)

=[(x+3)2−y2]:(x+y+3)[(x+3)2−y2]:(x+y+3)

=(x+3−y)(x+3+y):(x+y+3)(x+3−y)(x+3+y):(x+y+3)

= x+3−yx+3−y

=