Tính tích của phương trình sau:

Question

Tính tích: P=(1+ $\frac{7}{9}$) ( 1+ $\frac{7}{20}$) ( 1+ $\frac{7}{33}$)+...+ ( 1+$\frac{7}{2900}$ )

Answer 1

P=(1+79).(1+720).(1+733)...(1+72900)P=(1+79).(1+720).(1+733)...(1+72900)

P=169.2720.4033...29072900P=169.2720.4033...29072900

P=2.81.9.3.92.10.4.103.11...51.5750.58P=2.81.9.3.92.10.4.103.11...51.5750.58

P= 51.858P= 51.858

P= 20429