a) x3−2x2+x=x(x2−2x+1)x3−2x2+x=x(x2−2x+1)=x(x−1)2=x(x−1)2
b) 2x2+4x+2−2y22x2+4x+2−2y2
=2[(x2+2x+1)−y2]=2[(x2+2x+1)−y2]
=2[(x+1)2−y2]=2[(x+1)2−y2]
=2(x+1−y)(x+1+y)=2(x+1−y)(x+1+y)
c) 2xy−x2−y2+162xy−x2−y2+16
=16−(x2−2xy+y2)=16−(x2−2xy+y2)
=42−(x−y)2=42−(x−y)2
=(4–x+y)(4+x–y)