\(\text{Theo đề ta có: }(3-n)\ \vdots\ ( n+5) \)
\(\Rightarrow (-5-n+8)\ \vdots\ (n+5)\)
\(\Rightarrow -(n+5)+8\ \vdots\ (n+5)\)
\(\text{Mà }-(n+5)\ \vdots \ (n+5)\Rightarrow8\ \vdots\ (n+5)\)
\(\Rightarrow (n+5)\in Ư(8)=\{\pm1;\pm2;\pm4;\pm8\}\)
\(\text{Lập bảng}\)
\(n+5\) |
\(-8\) |
\(-4\) |
\(-2\) |
\(-1\) |
\(1\) |
\(2\) |
\(4\) |
\(8\) |
\(n\) |
\(-13\) |
\(-9\) |
\(-7\) |
\(-6\) |
\(-4\) |
\(-3\) |
\(-1\) |
\(3\) |
\(\text{Vậy n}\in\{-13;-9;-7;-6;-4;-3;-1;3\}\)
Tick mình nha