Ta có:
(18x5−27x3+3x):(5xn)=18x5:5xn−27x3:5xn+3x:5xn(18x5−27x3+3x):(5xn)=18x5:5xn−27x3:5xn+3x:5xn
=185.x5−n−275x3−n+35x1−n=185.x5−n−275x3−n+35x1−n
Để phép chia hết thì: 5−n;3−n;1−n≥05−n;3−n;1−n≥0
=> 1−n≥0⇔n≤11−n≥0⇔n≤1 và n∈Nn∈N
Vậy n=0;1
tick cho mk nha bn!!!