\(|x+ 45- 40| + |y+ 10- 11| \leq 0\) (1)
\(\Leftrightarrow |x+5|+|y-1| \leq 0\)
Ta có: \(\left\{\begin{matrix}
|x+5| \ge 0 \\
|y-1| \ge 0
\end{matrix}\right.
\forall x \in \mathbb{Z}\)
\(\Rightarrow (1) \Leftrightarrow \left\{\begin{matrix}
|x+5| = 0 \\
|y-1| = 0
\end{matrix}\right.\)
\(\Leftrightarrow \left\{\begin{matrix}
x = -5 \\
y= 1
\end{matrix}\right.\)
KL: .................
tuyen23052014600 
phamngoctienpy1987844 
manhlecong680419 