Chọn A
Ta có \(f'\left(x\right)=\frac{1}{2\sqrt{x} } \cos \sqrt{x} -\frac{1}{2\sqrt{x} } \sin \sqrt{x} .\)
Do đó \(f'\left(\frac{\pi ^{2} }{16} \right)=\frac{1}{2\sqrt{\frac{\pi ^{2} }{16} } } \cos \sqrt{\frac{\pi ^{2} }{16} } -\frac{1}{2\sqrt{\frac{\pi ^{2} }{16} } } \sin \sqrt{\frac{\pi ^{2} }{16} }\)
\( =\frac{2}{\pi } \cos \left(\frac{\pi }{4} \right)-\frac{2}{\pi } \sin \left(\frac{\pi }{4} \right)=0=0+0\pi .\)