Vì \(x^{2} +5\geq 5> 0\Rightarrow \left | x^{2} +5 \right |=x^{2} +5\)
Xét \(1-2x \geq 0\Rightarrow x\leq \frac{1}{2}\), suy ra:
\(C=x^2+5-3(1-2x) -x^2+10=6x+ 12 \)
Xét \(1-2x < 0\Rightarrow x> \frac{1}{2}\), suy ra:
\(C=x^2+5-3(2x-1) -x^2+10=-6x+18\)