\(C=1.4+2.5+...+n(n+3)\)
\(=1(1+3)+2(2+3)+...+n(n+3)\)
\(=1^2+3.1+2^2+3.2+...+n^2+3.n\)
\(=(1^2+2^2+...+n^2)+3(1+2+...+n)\)
\(=\dfrac{n(n+1)(2n+1)}{6}+3.\dfrac{n(n+1)}{2}\)
\(=\dfrac{n(n+1)}{2}.\begin{pmatrix}
\dfrac{2n+1}{3}+3
\end{pmatrix}\)
\(=\dfrac{n(n+1)(2n+10)}{6}=\dfrac{n(n+1)(n+5)}{3}\)
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