Gọi \(n_X=3a,n_Y=a\)
Ta có:
\(n_{KOH}=3n_X+n_Y=3\times 3a+a=0,5\)
\(\Rightarrow a=0,05\)
BTKL:
\(m=143,2+0,5\times 56-0,05\times 3\times 92-0,05\times 18=156,5(g)\)
Z gồm:
\(C_{15}H_{31}COOK:a (mol)\)
\(C_{17}H_{35}COOK:b(mol)\)
\(C_{17}H_{33}COOK:c(mol)\)
Ta có:
\(294a+322b+318c=156,5\)
\(a+b+c=0,5\)
\(c=0,15\)
\(\Rightarrow a=0,15;b=0,2;c=0,15\)
%\(m_{C_{15}H_{31}COOK}=\frac{0,15 \times 294}{156,5} \times 100=28,18\)%