\(x^2+y^2=2023\)
\(\Leftrightarrow x^2-y^2=2023\)
\(\Leftrightarrow (x-y)(x+y)=2023\)
Mà: \(x, y \epsilon \mathbb{N}\)
\(\Rightarrow (x-y),(x+y)\epsilon Ư(2023)={1; 7; 17; 119; 289; 2023}\)
x+y |
2023 |
289 |
119 |
x-y |
1 |
7 |
17 |
x |
1012 |
148 |
68 |
y |
1011 |
141 |
51 |
Vậy: \((x; y)\epsilon {{(1012; 1011); (148; 141); (68; 51)}}\)
_Chúc bạn học tốt_