a)Ta có:
2x2−7x+3=2x2−6x−x+3=2x(x−3)−(x−3)=(2x−1)(x−3)2x2−7x+3=2x2−6x−x+3=2x(x−3)−(x−3)=(2x−1)(x−3)
⟹x=3;x=12⟹x=3;x=12 là nghiệm của đa thức.
b)Ta có:10x2−29x+10=10x2−25x−4x+10=5x(2x−5)−2(2x−5)=(2x−5)(5x−2)10x2−29x+10=10x2−25x−4x+10=5x(2x−5)−2(2x−5)=(2x−5)(5x−2)
⟹...
c)Ta có:6x2−13x+6=6x2−4x−9x+6=2x(3x−2)−3(3x−2)=(2x−3)(3x−2)6x2−13x+6=6x2−4x−9x+6=2x(3x−2)−3(3x−2)=(2x−3)(3x−2)
⟹...