+
( 1 )
=> 5S = 5.( 5^1 + 5^2 + 5^3 + ... + 5^96 )
=> 5S = 5^2 + 5^3 + 5^4 + ... + 5^97 ( 2 )
( 1 ) , ( 2 ) => 5S - S = ( 5^2 + 5^3 + 5^4 + ... + 5^97 ) - ( 5^1 + 5^2 + 5^3 + ... + 5^96 )
=> 4S = 5^97 - 5
=> S = ( 5^97 - 5 ) : 4
+ 125 = 5^3
=> S = ((5^97 - 5 ) : 4 ) : 5^3
=> S = ( 5^/94 - 5 ) : 4
Vậy S chia hết cho 125 ( đpcm )