\(\text{Ta có: }(n+3)\ \vdots\ (2n-2)\)
\(\Rightarrow 2(n+3)\ \vdots\ (2n-2)\)
\((2n+6)\ \vdots\ (2n-2)\)
\((2n+8-2)\ \vdots\ (2n-2)\)
\((2n-2)\ \vdots\ (2n-2)\Rightarrow 8\ \vdots\ (2n-2)\)
\((2n-2)\in Ư(8)
\)
\(Ư(8)=\{\pm1;\pm2;\pm4;\pm8\}\)
\((2n-2)\in\{\pm1;\pm2;\pm4;\pm8\}\)
\(\text{Lập bảng:}\)
\(2n-2\) |
\(-8
\) |
\(-4\) |
\(-2\) |
\(-1\) |
\(1\) |
\(2\) |
\(4\) |
\(8\) |
\(n\) |
\(-3\) |
\(-1\) |
\(0\) |
\(\dfrac{1}{2}\) |
\(\dfrac{3}{2}\) |
\(2\) |
\(3\) |
\(5\) |
\(\text{Ta có: n là số tự nhiên}\)
\(\Rightarrow n=\{2;3;5\}\)
Tick mình nha