\(A= 16^{505} + 2^{2022}\)
\(A= (2^4)^{505} + 2^{2022}\)
\(A= 2^{2.505} + 2^{2022}\)
\(A= 2^{2020} + 2^{2020}.2^2\)
\(A= 2^{2020}.(1+2^2)\)
\(A= 2^{2020}.(1+4)\)
\(A= 2^{2020}.5\)
Mà \(\begin{matrix}
5\vdots 5
\end{matrix}\)
\(\Rightarrow 2^{2020}.5 \vdots5\)
Vậy \(A \vdots 5\)
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