Ta chọn câu C
Gọi số phức \( z=a+bi\, ;a,b\in {\rm R}.\)
Ta có
\(\begin{array}{l} {\left(1+2i\right)z+\left(2-3i\right)\overline{z}=-2-2i\Leftrightarrow \left(1+2i\right)\left(a+bi\right)+\left(2-3i\right)\left(a-bi\right)=-2-2i} \\ {\Leftrightarrow a+bi+2ai+2bi^{2} +2a-2bi-3ai+3bi^{2} =-2-2i} \\ {\Leftrightarrow 3a-5b+\left(-a-b\right)i=-2-2i} \\ {\Leftrightarrow \left\{\begin{array}{l} {3a-5b=-2} \\ {-a-b=-2} \end{array}\right. \Leftrightarrow \left\{\begin{array}{l} {a=1} \\ {b=1} \end{array}\right. \Rightarrow z=1+i} \end{array}\)