Question

Tìm thành phần % theo khối lượn các ng.tố hoá học nhữn hợp chất Na2SO4, CaCO3, Al2(SO4)3, NaHCO3, Ca(OH)2 ?

Answer 1

MNa2SO4 = 23.2+32+16.4 = 142 g/mol

=> %Na/Na2SO4 = 100.23.2/142 = 32,39%

=> %S/Na2SO4   = 100.32/142 = 32,39% = 22.54%

=> %O/Na2SO4   = 100.16.4/142 = 45,07%

 

MCaCO3 = 40+12+16.3 = 100 g/mol

=> %Ca/CaCO3 = 100.40/100 = 40%

=> %C/CaCO3   = 100.12/100 = 12%

=> %O/CaCO3   = 100.16.3/100=48%

 

MAl2(SO4)3 = 27.2+3(32+16.4) = 342 g/mol

=> %Al/Al2(SO4)3 = 100.27.2/342 = 15,79%

=> %S/Al2(SO4)3  = 100.32/342 = 28,07%

=> %O/Al2(SO4)3 = 100.16.12/342 = 56,14%

 

MCa(OH)2 = 40+2(1+16) = 74 g/mol

=> %Ca/Ca(OH)2 = 100.40/74 = 54,05%

=> %O/Ca(OH)2  = 100.32/74 = 43,24%

=> %O/Ca(OH)2  = 100.2/74 = 2,71%

 

MNaHCO3 = 23+1+12+16.3 = 84 g/mol

=> %Na/NaHCO3 = 100.23/84 = 27,38%

=> %H/NaHCO3   = 100.1/84 = 1,19% 

=> %C/NaHCO3   = 100.12/84 = 14,29%

=> %O/NaHCO3   = 100.16.3/84 = 57,14%