a) \(C_{2}H_{4} + Br_{2} \rightarrow C_{2}H_{4}Br_{2} \)
\(C_{2}H_{2} + 2Br_{2} \rightarrow C_{2}H_{2}Br_{4} \)
\(C_{2}H_{2} + 2AgNO_{3} + 2NH_{3} + 2H_{2}O \rightarrow CH_{3}COOH + 2Ag + 2NH_{4}NO_{3} \)
b) %\(V_{C_{2}H_{6}} = \frac{1,68}{6,72} = 25\)%
\(n_{Ag} = \frac{24,24}{108} =
\frac{101}{450}mol\)
\(V_{C_{2}H_{6}} = \frac{101}{450}.0,5.22,4 = \frac{2828}{1125}l\)
=> %V C2H6 = 37,4%
%C2H4 = 37,6%