Chọn A
=Ta có:
\(\int _{1}^{3}f \left(x\right){\rm d}x=\int _{1}^{2}f \left(x\right){\rm d}x+\int _{2}^{3}f \left(x\right){\rm d}x\)
\(\Leftrightarrow \int _{2}^{3}f \left(x\right){\rm d}x=\int _{1}^{3}f \left(x\right){\rm d}x-\int _{1}^{2}f \left(x\right){\rm d}x\)
\(
\Leftrightarrow \int _{2}^{3}f \left(x\right){\rm d}x=1-\left(-3\right)=4.\)