Tích Mình NHA
mCuSO4bđ=600∗10100=60(g)mCuSO4bđ=600∗10100=60(g)
=>mH2Obđ=600−60=540(g)mH2Obđ=600−60=540(g)
=>mH2Osau=540−400=140(g)mH2Osau=540−400=140(g)
ta có 600g dung dịch CuSO4CuSO4 10% chứa 540g H2OH2O
=> x(g) dung dịch CuSO4CuSO4 10% chứa 140g H2OH2O
=>x=140∗600540=14009(g)x=140∗600540=14009(g)
=>mCuSO4sau=14009∗20100=2809(g)mCuSO4sau=14009∗20100=2809(g)
=>nCuSO4sau=2809160=736nCuSO4sau=2809160=736
=>mCuSO4.5H2O=736∗160+736∗5∗18=87518(g)mCuSO4.5H2O=736∗160+736∗5∗18=87518(g)