\(\frac{1}{x}+\frac{3}{5}=\frac{4}{5}\)
\(\frac{3}{2} +\frac{2}{8}=\frac{x}{4}\)
\(\frac{2}{x} =\frac{x}{2}\)
\(\frac{1}{x}=\frac{4}{5}-\frac{3}{5}\) \(\frac{1}{x}=\frac{1}{5}\) => x=5
\(\frac{12}{8}+\frac{2}{8}=\frac{x}{4}\) \(\frac{7}{4}=\frac {x}{4}\) =>x=7
\(\frac{2}{x} = \frac{x}{2}\) => \(x^2=2^2\)
=>x=2
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